5c^2+21c-20=

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Solution for 5c^2+21c-20= equation:


Simplifying
5c2 + 21c + -20 = 0

Reorder the terms:
-20 + 21c + 5c2 = 0

Solving
-20 + 21c + 5c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-5 + -1c)(4 + -5c) = 0

Subproblem 1

Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5

Subproblem 2

Set the factor '(4 + -5c)' equal to zero and attempt to solve: Simplifying 4 + -5c = 0 Solving 4 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5c = 0 + -4 -5c = 0 + -4 Combine like terms: 0 + -4 = -4 -5c = -4 Divide each side by '-5'. c = 0.8 Simplifying c = 0.8

Solution

c = {-5, 0.8}

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